4u^2+5u-9=0

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Solution for 4u^2+5u-9=0 equation: 



4u^2+5u-9=0

a = 4; b = 5; c = -9;
Δ = b2-4ac
Δ = 52-4·4·(-9)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$


$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-13}{2*4}=\frac{-18}{8}
=-2+1/4
$


$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+13}{2*4}=\frac{8}{8}
=1
$

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